Bar Bending Schedule for Beam

Bar Bending Schedule for Beam

We will take one simple example for reinforcement quantity calculations for a concrete beam.

RCC Beam Reinforcement Calculation:

Consider a beam of clear length of 4m (4000mm), 350mm wide by 450mm depth. It consists of 2-12 diameter bars at top, and 2-16 diameter and 1 – 12 diameter bars at the bottom. Diameter of stirrup is 8mm spaced at 150mm center to center. Clear cover to reinforcement provided is 30mm.

Fig: RCC Beam Reinforcement Details


Fig: RCC Beam Cross-Section
Now we will calculate the length of reinforcement based on shapes of reinforcement required for reinforced concrete beam in above example.
We will start with bottom reinforcement, B1.
Bar shape of B1 is as shown below:

Length of B1 = clear distance between walls + 2 x width of walls – 2 x bar cover + 2 x bend length
Bend length = 6 x 16 = 96 consider as 100mm
Bend length is calculated as 6 x diameter of bar for reinforcement conforming to IS: 1786-1961
Length of B1 = 4000 + 2 x 250 – 2 x 30 + 2 x100 = 4640mm
Length of bar B2 is calculated based on shape of this bar. This bar bends up near the support as shown below:



Length of bar B2: A + B + C = 4000 + 2 x 250 – 2 x 30 + (1.414xh – h)
h = 450 – 2 x 30 – 2 x 12 – 2 x 12/2 = 354mm
B2 = 4000 + 2 x 250 – 2 x 30 + (1.414×354 – 354) = 4586.5 = 4520mm
Length of Bar T1 = 4000 + 2 x 230 -2 x 40 = 4380mm
Length of Stirrups S1:


Stirrups are spaced at 150mm center to center. Stirrups are provided between walls or support for a beam.
No. of stirrups required for given beam = 
Length p = 450 – 2 x 30 – 8 = 382mm
Length q = 350 – 2 x 30 – 8 = 282mm
Therefore length of 1 stirrup S1 = 2 x (282 + 382 + 90*) = 1378 mm
*Where 90mm is the minimum hook length as per IS 2502 – Table – II.

Bar Bending Schedule for RCC Beam: